(7x-1)(x^2-3x+1)=0

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Solution for (7x-1)(x^2-3x+1)=0 equation: 


Simplifying
(7x + -1)(x2 + -3x + 1) = 0

Reorder the terms:
(-1 + 7x)(x2 + -3x + 1) = 0

Reorder the terms:
(-1 + 7x)(1 + -3x + x2) = 0

Multiply (-1 + 7x) * (1 + -3x + x2)
(-1(1 + -3x + x2) + 7x * (1 + -3x + x2)) = 0
((1 * -1 + -3x * -1 + x2 * -1) + 7x * (1 + -3x + x2)) = 0
((-1 + 3x + -1x2) + 7x * (1 + -3x + x2)) = 0
(-1 + 3x + -1x2 + (1 * 7x + -3x * 7x + x2 * 7x)) = 0
(-1 + 3x + -1x2 + (7x + -21x2 + 7x3)) = 0

Reorder the terms:
(-1 + 3x + 7x + -1x2 + -21x2 + 7x3) = 0

Combine like terms: 3x + 7x = 10x
(-1 + 10x + -1x2 + -21x2 + 7x3) = 0

Combine like terms: -1x2 + -21x2 = -22x2
(-1 + 10x + -22x2 + 7x3) = 0

Solving
-1 + 10x + -22x2 + 7x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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